2019-09-18 10:26:44 163浏览
本篇文章扣丁学堂Java培训小编给读者们简单分享一下如何用C#随机数生成字母金字塔,具有一定的参考价值,感文中有详细的代码列出供感兴趣的小伙伴参考,想要了解的小伙伴就随小编来看一下具体内容吧。
	
	
	
	
	 
		1、代码实现:
	 
		 
		 
		2、运行结果:
	
	static void Main(string[] args)
    {  
      showNpoint(25);
      Console.ReadKey();
    }
    private static void showNpoint(int count)
    {
      Random r = new Random();
      string[] strE = { "A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"};
      for (int i = 1; i <=count; i++)
      {
        for (int j = 1; j <=count-i; j++)
        {
          Console.Write(" ");
        }
        for (int k = 1; k <= 2*i-1; k++)
        {
          Console.Write(strE[r.Next(0,25)]);
        }
        Console.WriteLine();
      }
    }
	
	
	
	
以上就是扣丁学堂Java在线学习小编给大家分享的如何用C#随机数生成字母金字塔,希望对小伙伴们有所帮助,想要了解更多内容的小伙伴可以登录扣丁学堂官网咨询。
	
想要学好Java开发小编给大家推荐口碑良好的扣丁学堂,扣丁学堂有专业老师制定的Java学习路线图辅助学员学习,此外还有与时俱进的Java课程体系和Java视频教程供大家学习,想要学好Java开发技术的小伙伴快快行动吧。扣丁学堂Java技术交流群:850353792。
	
	
	 
		 
		 
		     【关注微信公众号获取更多学习资料】        【扫码进入JavaEE/微服务VIP免费公开课】