2019-04-03 13:51:25 1929浏览
今天扣丁学堂Python培训老师给大家分享一篇关于Python零基础入门之元组列表字典的详细介绍,文中通过示例代码介绍的非常详细,下面我们一起来看一下吧。
a_tuple = (12, 3, 5, 15 , 6) another_tuple = 12, 3, 5, 15 , 6
a_list = [12, 3, 67, 7, 82]
for content in a_list: print(content) """ 12 3 67 7 82 """ for content_tuple in a_tuple: print(content_tuple) """ 12 3 5 15 6 """
for index in range(len(a_list)): print("index = ", index, ", number in list = ", a_list[index]) """ index = 0 , number in list = 12 index = 1 , number in list = 3 index = 2 , number in list = 67 index = 3 , number in list = 7 index = 4 , number in list = 82 """ for index in range(len(a_tuple)): print("index = ", index, ", number in tuple = ", a_tuple[index]) """ index = 0 , number in tuple = 12 index = 1 , number in tuple = 3 index = 2 , number in tuple = 5 index = 3 , number in tuple = 15 index = 4 , number in tuple = 6 """
a = [1,2,3,4,1,1,-1] a.append(0) # 在a的最后面追加一个0 print(a) # [1, 2, 3, 4, 1, 1, -1, 0]
a = [1,2,3,4,1,1,-1] a.insert(1,0) # 在位置1处添加0 print(a) # [1, 0, 2, 3, 4, 1, 1, -1]
a = [1,2,3,4,1,1,-1] a.remove(2) # 删除列表中第一个出现的值为2的项 print(a) # [1, 3, 4, 1, 1, -1]
a = [1,2,3,4,1,1,-1] print(a[0]) # 显示列表a的第0位的值 # 1 print(a[-1]) # 显示列表a的最末位的值 # -1 print(a[0:3]) # 显示列表a的从第0位 到 第2位(第3位之前) 的所有项的值 # [1, 2, 3] print(a[5:]) # 显示列表a的第5位及以后的所有项的值 # [1, -1] print(a[-3:]) # 显示列表a的倒数第3位及以后的所有项的值 # [1, 1, -1]
a = [1,2,3,4,1,1,-1] print(a.index(2)) # 显示列表a中第一次出现的值为2的项的索引 # 1 print(a.count(-1)) # 1
a = [4,1,2,3,4,1,1,-1] a.sort() # 默认从小到大排序 print(a) # [-1, 1, 1, 1, 2, 3, 4, 4] a.sort(reverse=True) # 从大到小排序 print(a) # [4, 4, 3, 2, 1, 1, 1, -1]
a = [1,2,3,4,5] # 一行五列 multi_dim_a = [[1,2,3], [2,3,4], [3,4,5]] # 三行三列
print(a[1]) # 2 print(multi_dim_a[0][1]) # 2
a_list = [1,2,3,4,5,6,7,8] d1 = {'apple':1, 'pear':2, 'orange':3} d2 = {1:'a', 2:'b', 3:'c'} d3 = {1:'a', 'b':2, 'c':3} print(d1['apple']) # 1 print(a_list[0]) # 1 del d1['pear'] print(d1) # {'orange': 3, 'apple': 1} d1['b'] = 20 print(d1) # {'orange': 3, 'b': 20, 'pear': 2, 'apple': 1}
def func(): return 0 d4 = {'apple':[1,2,3], 'pear':{1:3, 3:'a'}, 'orange':func} print(d4['pear'][3]) # a
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